Integrand size = 19, antiderivative size = 32 \[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\frac {\sqrt {-1+a x} \text {arccosh}(a x)^2}{2 a \sqrt {1-a x}} \]
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Time = 0.02 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {5892} \[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\frac {\sqrt {a x-1} \text {arccosh}(a x)^2}{2 a \sqrt {1-a x}} \]
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Rule 5892
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {-1+a x} \text {arccosh}(a x)^2}{2 a \sqrt {1-a x}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.41 \[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\frac {\sqrt {-1+a x} \sqrt {1+a x} \text {arccosh}(a x)^2}{2 a \sqrt {1-a^2 x^2}} \]
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Time = 0.46 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.59
method | result | size |
default | \(-\frac {\sqrt {-\left (a x -1\right ) \left (a x +1\right )}\, \sqrt {a x -1}\, \sqrt {a x +1}\, \operatorname {arccosh}\left (a x \right )^{2}}{2 \left (a^{2} x^{2}-1\right ) a}\) | \(51\) |
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\[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {arcosh}\left (a x\right )}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]
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\[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\int \frac {\operatorname {acosh}{\left (a x \right )}}{\sqrt {- \left (a x - 1\right ) \left (a x + 1\right )}}\, dx \]
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\[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {arcosh}\left (a x\right )}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]
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\[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {arcosh}\left (a x\right )}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]
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Timed out. \[ \int \frac {\text {arccosh}(a x)}{\sqrt {1-a^2 x^2}} \, dx=\int \frac {\mathrm {acosh}\left (a\,x\right )}{\sqrt {1-a^2\,x^2}} \,d x \]
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